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[]kikumbob
om nom nom nom nom
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im confused to how Harry thought I was being so dumb..8O
12.09.04 20:00
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[]Star Worms
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Easy to make that mistake (j/k but you were asking for it;))

Anyway - you lazy lot haven't been updating the scores so if you don't then I won't be handing any money out.

*hint hint* someone please update it.

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12.09.04 20:51
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[G]the candy man
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yeah and DJ you said the contest was for 24 for hours and nearest one gets the piiunt. Its bin more than 24 hours.

BTW did i get the point on the hottest one?
12.09.04 20:53
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[]HarrY
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yes you did,.
people don't seem to be reading today>:E

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12.09.04 21:10
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[G]dj canada
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Candyman gets both points as he was the closest for the coldest temp and got the hotest temp dead on.

Lowest Temperature is -129F (-89.4C) and was recorded at Vostok, Antarctica on July 21 1983

DJ Canada 2
The candy Man 2

Your turn Candy Boy!


Quoted :: HarrY

people don't seem to be reading today>:E


Poeple never read anything in the forums... Look at the dreams threads... instead of staying on topic people randomly post what deams THEY HAVE....

*makes random noise*
"bllleeehhhhaaaalllllaaaaaaaaaarrrrruuuppppyyyyyy"
12.09.04 22:09
Post #50		Last edited: 12.09.04 22:12 (DJ Canada - 1 times) [Hide Sig (0)] [Profile] [Quote]
[G]the candy man
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Ok im goin got school now so give me the day to think about it :)

EDIT : ok im back and i have a hard maths question...well i think its hard

what is this problem reduced?

((3m^1/6)(n^1/3))^2
-------------------
( 4n^-2/3)^2

Good look and happy Mathing. ill give you 3-4 days and if no on gets it, ill either give it to the nearest one or...do another
13.09.04 07:09
Post #51		Last edited: 13.09.04 15:54 (The candy Man - 1 times) [Hide Sig (0)] [Profile] [Quote]
[G]dj canada
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YEAH RIGHT!
Math Questions.... Forget that....

Is it 1?
8O
13.09.04 16:52
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[G]the candy man
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LOL
Not even close, ill give a slight clue.
Its not a number
13.09.04 17:01
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[]HarrY
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how can it be a number?
it isn't answer were looking for.
it's a simplyfied version of that problem.

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13.09.04 17:06
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[]Dingbats
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((3m^1/6)(n^1/3))^2
-------------------
( 4n^-2/3)^2

Well...

3m2/6*n2/3
----------------------
4n-1/3

Just a guess. You have to be some kind of maths freak to know this... 8O
13.09.04 17:28
Post #55		Last edited: 13.09.04 17:29 (Dingbats - 1 times) [Softbrain Games] [Hide Sig (2)] [Profile] [Quote]
[G]the candy man
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lol you arnt even close.
I didnt actually no this, but i saw the question somewere and noted ot down.
13.09.04 19:34
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[S]ReadMe
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well the m goes nowhere, and ascii maths notation is horrible, but heres the solution as far as i can see if m and n aren't given values and theres no other equation to factor in

¾m1/6n

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13.09.04 21:44
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[]Glenn
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I'm just throwing this answer out there, and I'm probably wrong (paranthesis added for clarity)...

(16 * (n ^ 4)) * ((12 * m) ^ 1/3)

Which in words is:

16 times n to the 4th power, multiplied by the 3rd root of the quantity 12 times m.
14.09.04 00:13
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[G]the candy man
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i think this is maybe a bit to hard?
ill do another question.

First one to guess how many contacts i have on my MSN wins the point.
14.09.04 16:31
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[]HarrY
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135

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14.09.04 16:46
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